A common algorithm with O (log n) time complexity is Binary Search whose recursive relation is T (n/2) + O (1) i.e. at every subsequent level of the tree you divide problem into half and do constant amount of additional work.
How would you go about testing all possible combinations of additions from a given set N of numbers so they add up to a given final number? A brief example: Set of numbers to add: N = {1,5,22,15,0...
This is a simple question from algorithms theory. The difference between them is that in one case you count number of nodes and in other number of edges on the shortest path between root and concrete
Robust peak detection algorithm (using z-scores) I came up with an algorithm that works very well for these types of datasets. It is based on the principle of dispersion: if a new datapoint is a given x number of standard deviations away from a moving mean, the algorithm gives a signal. The algorithm is very robust because it constructs a separate moving mean and deviation, such that previous ...
I have a line from A to B and a circle positioned at C with the radius R. What is a good algorithm to use to check whether the line intersects the circle? And at what coordinate along the circles ...
While solving a geometry problem, I came across an approach called Sliding Window Algorithm. Couldn't really find any study material/details on it. What is the algorithm about?
Why could this be useful? Dependant on the morphing algorithm you use, there may be a relationship between similarity of images, and some parameters of the morphing algorithm. In a grossly over simplified example, one algorithm might execute faster when there are less changes to be made.
The algorithm is ray-casting to the right. Each iteration of the loop, the test point is checked against one of the polygon's edges. The first line of the if-test succeeds if the point's y-coord is within the edge's scope. The second line checks whether the test point is to the left of the line (I think - I haven't got any scrap paper to hand to check). If that is true the line drawn ...
I came up with this algorithm for matrix multiplication. I read somewhere that matrix multiplication has a time complexity of o(n^2). But I think my this algorithm will give o(n^3). I don't know ...
2 Here's an algorithm faster than everybody else's algorithm for most cases. It's new and elegant. We spend O(n * log(n)) time building a table that will allow us to test point-in-polygon in O(log(n) + k) time. Rather than ray-tracing or angles, you can get significantly faster results for multiple checks of the same polygon using a scanbeam table.
